The San Francisco 49ers wasted no time addressing their need at linebacker in the early part of free agency.
Ian Rapoport of NFL Network reports that the 49ers have agreed to a four-year, $54 million deal with former Tampa Bay Buccaneers linebacker Kwon Alexander.
Source: The #49ers are signing LB Kwon Alexander to a 4-year deal worth $54M.
— Ian Rapoport (@RapSheet) March 11, 2019
Earlier on Monday, Alexander disputed a report indicating he had already said goodbye to his former teammates in Tampa. It now appears he was just trying to keep a lid on the news for as long as he could.
Alexander’s season was cut short by a torn ACL last year, but he has been one of the best linebackers in football since the Bucs drafted him in 2015. He had 93 or more total tackles in each of the three seasons before that.
